-4(2y-5)+3y=5(y+7)

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Solution for -4(2y-5)+3y=5(y+7) equation: 



-4(2y-5)+3y=5(y+7)

We move all terms to the left:

-4(2y-5)+3y-(5(y+7))=0

We add all the numbers together, and all the variables

3y-4(2y-5)-(5(y+7))=0

We multiply parentheses

3y-8y-(5(y+7))+20=0



We calculate terms in parentheses: -(5(y+7)), so:

5(y+7)

We multiply parentheses

5y+35

Back to the equation:

-(5y+35)



We add all the numbers together, and all the variables

-5y-(5y+35)+20=0

We get rid of parentheses

-5y-5y-35+20=0

We add all the numbers together, and all the variables

-10y-15=0

We move all terms containing y to the left, all other terms to the right

-10y=15

y=15/-10

y=-1+1/2

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