-4(2y-3)=-6(y-1)

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Solution for -4(2y-3)=-6(y-1) equation: 



-4(2y-3)=-6(y-1)

We move all terms to the left:

-4(2y-3)-(-6(y-1))=0

We multiply parentheses

-8y-(-6(y-1))+12=0



We calculate terms in parentheses: -(-6(y-1)), so:

-6(y-1)

We multiply parentheses

-6y+6

Back to the equation:

-(-6y+6)



We get rid of parentheses

-8y+6y-6+12=0

We add all the numbers together, and all the variables

-2y+6=0

We move all terms containing y to the left, all other terms to the right

-2y=-6

y=-6/-2

y=+3

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