-4(2y-3)+4y=6(y+5)

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Solution for -4(2y-3)+4y=6(y+5) equation: 



-4(2y-3)+4y=6(y+5)

We move all terms to the left:

-4(2y-3)+4y-(6(y+5))=0

We add all the numbers together, and all the variables

4y-4(2y-3)-(6(y+5))=0

We multiply parentheses

4y-8y-(6(y+5))+12=0



We calculate terms in parentheses: -(6(y+5)), so:

6(y+5)

We multiply parentheses

6y+30

Back to the equation:

-(6y+30)



We add all the numbers together, and all the variables

-4y-(6y+30)+12=0

We get rid of parentheses

-4y-6y-30+12=0

We add all the numbers together, and all the variables

-10y-18=0

We move all terms containing y to the left, all other terms to the right

-10y=18

y=18/-10

y=-1+4/5

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