-4(2y+2)-12=-6(y+5)+2y

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Solution for -4(2y+2)-12=-6(y+5)+2y equation: 



-4(2y+2)-12=-6(y+5)+2y

We move all terms to the left:

-4(2y+2)-12-(-6(y+5)+2y)=0

We multiply parentheses

-8y-(-6(y+5)+2y)-8-12=0



We calculate terms in parentheses: -(-6(y+5)+2y), so:

-6(y+5)+2y

We add all the numbers together, and all the variables

2y-6(y+5)

We multiply parentheses

2y-6y-30

We add all the numbers together, and all the variables

-4y-30

Back to the equation:

-(-4y-30)



We add all the numbers together, and all the variables

-8y-(-4y-30)-20=0

We get rid of parentheses

-8y+4y+30-20=0

We add all the numbers together, and all the variables

-4y+10=0

We move all terms containing y to the left, all other terms to the right

-4y=-10

y=-10/-4

y=2+1/2

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