-4(2x-3)+x-3=-3x(x+2)-4x+5

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Solution for -4(2x-3)+x-3=-3x(x+2)-4x+5 equation: 



-4(2x-3)+x-3=-3x(x+2)-4x+5

We move all terms to the left:

-4(2x-3)+x-3-(-3x(x+2)-4x+5)=0

We add all the numbers together, and all the variables

x-4(2x-3)-(-3x(x+2)-4x+5)-3=0

We multiply parentheses

x-8x-(-3x(x+2)-4x+5)+12-3=0



We calculate terms in parentheses: -(-3x(x+2)-4x+5), so:

-3x(x+2)-4x+5

We add all the numbers together, and all the variables

-4x-3x(x+2)+5

We multiply parentheses

-3x^2-4x-6x+5

We add all the numbers together, and all the variables

-3x^2-10x+5

Back to the equation:

-(-3x^2-10x+5)



We add all the numbers together, and all the variables

-(-3x^2-10x+5)-7x+9=0

We get rid of parentheses

3x^2+10x-7x-5+9=0

We add all the numbers together, and all the variables

3x^2+3x+4=0

a = 3; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·3·4
Δ = -39
Delta is less than zero, so there is no solution for the equation

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