-4(2x-3)+6=-2(3x+1)+2x+8

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Solution for -4(2x-3)+6=-2(3x+1)+2x+8 equation: 



-4(2x-3)+6=-2(3x+1)+2x+8

We move all terms to the left:

-4(2x-3)+6-(-2(3x+1)+2x+8)=0

We multiply parentheses

-8x-(-2(3x+1)+2x+8)+12+6=0



We calculate terms in parentheses: -(-2(3x+1)+2x+8), so:

-2(3x+1)+2x+8

We add all the numbers together, and all the variables

2x-2(3x+1)+8

We multiply parentheses

2x-6x-2+8

We add all the numbers together, and all the variables

-4x+6

Back to the equation:

-(-4x+6)



We add all the numbers together, and all the variables

-8x-(-4x+6)+18=0

We get rid of parentheses

-8x+4x-6+18=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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