-4(2x+3)=6x-40

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Solution for -4(2x+3)=6x-40 equation: 



-4(2x+3)=6x-40

We move all terms to the left:

-4(2x+3)-(6x-40)=0

We multiply parentheses

-8x-(6x-40)-12=0

We get rid of parentheses

-8x-6x+40-12=0

We add all the numbers together, and all the variables

-14x+28=0

We move all terms containing x to the left, all other terms to the right

-14x=-28

x=-28/-14

x=+2

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