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-4(2x+2)+2=2(x-4)-2
We move all terms to the left:
-4(2x+2)+2-(2(x-4)-2)=0
We multiply parentheses
-8x-(2(x-4)-2)-8+2=0
We calculate terms in parentheses: -(2(x-4)-2), so:We add all the numbers together, and all the variables
2(x-4)-2
We multiply parentheses
2x-8-2
We add all the numbers together, and all the variables
2x-10
Back to the equation:
-(2x-10)
-8x-(2x-10)-6=0
We get rid of parentheses
-8x-2x+10-6=0
We add all the numbers together, and all the variables
-10x+4=0
We move all terms containing x to the left, all other terms to the right
-10x=-4
x=-4/-10
x=2/5
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