-4(2u-2)+3u=7(u+2)

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Solution for -4(2u-2)+3u=7(u+2) equation: 



-4(2u-2)+3u=7(u+2)

We move all terms to the left:

-4(2u-2)+3u-(7(u+2))=0

We add all the numbers together, and all the variables

3u-4(2u-2)-(7(u+2))=0

We multiply parentheses

3u-8u-(7(u+2))+8=0



We calculate terms in parentheses: -(7(u+2)), so:

7(u+2)

We multiply parentheses

7u+14

Back to the equation:

-(7u+14)



We add all the numbers together, and all the variables

-5u-(7u+14)+8=0

We get rid of parentheses

-5u-7u-14+8=0

We add all the numbers together, and all the variables

-12u-6=0

We move all terms containing u to the left, all other terms to the right

-12u=6

u=6/-12

u=-1/2

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