-4(2a-3)=1-2(10-2a)

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Solution for -4(2a-3)=1-2(10-2a) equation: 



-4(2a-3)=1-2(10-2a)

We move all terms to the left:

-4(2a-3)-(1-2(10-2a))=0

We add all the numbers together, and all the variables

-4(2a-3)-(1-2(-2a+10))=0

We multiply parentheses

-8a-(1-2(-2a+10))+12=0



We calculate terms in parentheses: -(1-2(-2a+10)), so:

1-2(-2a+10)

determiningTheFunctionDomain
-2(-2a+10)+1

We multiply parentheses

4a-20+1

We add all the numbers together, and all the variables

4a-19

Back to the equation:

-(4a-19)



We get rid of parentheses

-8a-4a+19+12=0

We add all the numbers together, and all the variables

-12a+31=0

We move all terms containing a to the left, all other terms to the right

-12a=-31

a=-31/-12

a=2+7/12

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