-4(2-y)+3y=3(y-3)

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Solution for -4(2-y)+3y=3(y-3) equation: 



-4(2-y)+3y=3(y-3)

We move all terms to the left:

-4(2-y)+3y-(3(y-3))=0

We add all the numbers together, and all the variables

-4(-1y+2)+3y-(3(y-3))=0

We add all the numbers together, and all the variables

3y-4(-1y+2)-(3(y-3))=0

We multiply parentheses

3y+4y-(3(y-3))-8=0



We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)



We add all the numbers together, and all the variables

7y-(3y-9)-8=0

We get rid of parentheses

7y-3y+9-8=0

We add all the numbers together, and all the variables

4y+1=0

We move all terms containing y to the left, all other terms to the right

4y=-1

y=-1/4

y=-1/4

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