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-4(2-y)+3y=3(y-1)
We move all terms to the left:
-4(2-y)+3y-(3(y-1))=0
We add all the numbers together, and all the variables
-4(-1y+2)+3y-(3(y-1))=0
We add all the numbers together, and all the variables
3y-4(-1y+2)-(3(y-1))=0
We multiply parentheses
3y+4y-(3(y-1))-8=0
We calculate terms in parentheses: -(3(y-1)), so:We add all the numbers together, and all the variables
3(y-1)
We multiply parentheses
3y-3
Back to the equation:
-(3y-3)
7y-(3y-3)-8=0
We get rid of parentheses
7y-3y+3-8=0
We add all the numbers together, and all the variables
4y-5=0
We move all terms containing y to the left, all other terms to the right
4y=5
y=5/4
y=1+1/4
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