-4(2+y)=3(y-4)

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Solution for -4(2+y)=3(y-4) equation: 



-4(2+y)=3(y-4)

We move all terms to the left:

-4(2+y)-(3(y-4))=0

We add all the numbers together, and all the variables

-4(y+2)-(3(y-4))=0

We multiply parentheses

-4y-(3(y-4))-8=0



We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)



We get rid of parentheses

-4y-3y+12-8=0

We add all the numbers together, and all the variables

-7y+4=0

We move all terms containing y to the left, all other terms to the right

-7y=-4

y=-4/-7

y=4/7

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