-4(1-2m)=3(2-m)+1

Solution for -4(1-2m)=3(2-m)+1 equation:

-4(1-2m)=3(2-m)+1

We move all terms to the left:

-4(1-2m)-(3(2-m)+1)=0

We add all the numbers together, and all the variables

-4(-2m+1)-(3(-1m+2)+1)=0

We multiply parentheses

8m-(3(-1m+2)+1)-4=0


We calculate terms in parentheses: -(3(-1m+2)+1), so:

3(-1m+2)+1

We multiply parentheses

-3m+6+1

We add all the numbers together, and all the variables

-3m+7

Back to the equation:

-(-3m+7)


We get rid of parentheses

8m+3m-7-4=0

We add all the numbers together, and all the variables

11m-11=0

We move all terms containing m to the left, all other terms to the right

11m=11

m=11/11

m=1