-4(1+2k)+3k=-3(3k-4)

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Solution for -4(1+2k)+3k=-3(3k-4) equation: 



-4(1+2k)+3k=-3(3k-4)

We move all terms to the left:

-4(1+2k)+3k-(-3(3k-4))=0

We add all the numbers together, and all the variables

-4(2k+1)+3k-(-3(3k-4))=0

We add all the numbers together, and all the variables

3k-4(2k+1)-(-3(3k-4))=0

We multiply parentheses

3k-8k-(-3(3k-4))-4=0



We calculate terms in parentheses: -(-3(3k-4)), so:

-3(3k-4)

We multiply parentheses

-9k+12

Back to the equation:

-(-9k+12)



We add all the numbers together, and all the variables

-5k-(-9k+12)-4=0

We get rid of parentheses

-5k+9k-12-4=0

We add all the numbers together, and all the variables

4k-16=0

We move all terms containing k to the left, all other terms to the right

4k=16

k=16/4

k=4

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