-4(-8y-3)=-4(3y-2)

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Solution for -4(-8y-3)=-4(3y-2) equation: 



-4(-8y-3)=-4(3y-2)

We move all terms to the left:

-4(-8y-3)-(-4(3y-2))=0

We multiply parentheses

32y-(-4(3y-2))+12=0



We calculate terms in parentheses: -(-4(3y-2)), so:

-4(3y-2)

We multiply parentheses

-12y+8

Back to the equation:

-(-12y+8)



We get rid of parentheses

32y+12y-8+12=0

We add all the numbers together, and all the variables

44y+4=0

We move all terms containing y to the left, all other terms to the right

44y=-4

y=-4/44

y=-1/11

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