-4(-7-b)=1/3(b+29)

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Solution for -4(-7-b)=1/3(b+29) equation: 



-4(-7-b)=1/3(b+29)

We move all terms to the left:

-4(-7-b)-(1/3(b+29))=0



Domain of the equation: 3(b+29))!=0

b∈R



We add all the numbers together, and all the variables

-4(-1b-7)-(1/3(b+29))=0

We multiply parentheses

4b-(1/3(b+29))+28=0

We multiply all the terms by the denominator


4b*3(b+29))-(1+28*3(b+29))=0

Wy multiply elements

12b^2(b+84b(b=0

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