-4(-6u+2)-6u=2(u-4)-4

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Solution for -4(-6u+2)-6u=2(u-4)-4 equation: 



-4(-6u+2)-6u=2(u-4)-4

We move all terms to the left:

-4(-6u+2)-6u-(2(u-4)-4)=0

We add all the numbers together, and all the variables

-6u-4(-6u+2)-(2(u-4)-4)=0

We multiply parentheses

-6u+24u-(2(u-4)-4)-8=0



We calculate terms in parentheses: -(2(u-4)-4), so:

2(u-4)-4

We multiply parentheses

2u-8-4

We add all the numbers together, and all the variables

2u-12

Back to the equation:

-(2u-12)



We add all the numbers together, and all the variables

18u-(2u-12)-8=0

We get rid of parentheses

18u-2u+12-8=0

We add all the numbers together, and all the variables

16u+4=0

We move all terms containing u to the left, all other terms to the right

16u=-4

u=-4/16

u=-1/4

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