-4(-5y+1)-5y=3(y-3)-4

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Solution for -4(-5y+1)-5y=3(y-3)-4 equation: 



-4(-5y+1)-5y=3(y-3)-4

We move all terms to the left:

-4(-5y+1)-5y-(3(y-3)-4)=0

We add all the numbers together, and all the variables

-5y-4(-5y+1)-(3(y-3)-4)=0

We multiply parentheses

-5y+20y-(3(y-3)-4)-4=0



We calculate terms in parentheses: -(3(y-3)-4), so:

3(y-3)-4

We multiply parentheses

3y-9-4

We add all the numbers together, and all the variables

3y-13

Back to the equation:

-(3y-13)



We add all the numbers together, and all the variables

15y-(3y-13)-4=0

We get rid of parentheses

15y-3y+13-4=0

We add all the numbers together, and all the variables

12y+9=0

We move all terms containing y to the left, all other terms to the right

12y=-9

y=-9/12

y=-3/4

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