-4(-5-b)=1/3*b+16)

Solution for -4(-5-b)=1/3*b+16) equation:

-4(-5-b)=1/3b+16)

We move all terms to the left:

-4(-5-b)-(1/3b+16))=0


Domain of the equation: 3b+16))!=0

b∈R


We add all the numbers together, and all the variables

-4(-1b-5)-(1/3b+16))=0

We multiply parentheses

4b-(1/3b+16))+20=0

We multiply all the terms by the denominator


4b*3b+16))+20-(1=0

We add all the numbers together, and all the variables

4b*3b=0

Wy multiply elements

12b^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{24}=0$