-4(-3z-5)=-(10z+8)-2

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Solution for -4(-3z-5)=-(10z+8)-2 equation: 



-4(-3z-5)=-(10z+8)-2

We move all terms to the left:

-4(-3z-5)-(-(10z+8)-2)=0

We multiply parentheses

12z-(-(10z+8)-2)+20=0



We calculate terms in parentheses: -(-(10z+8)-2), so:

-(10z+8)-2

We get rid of parentheses

-10z-8-2

We add all the numbers together, and all the variables

-10z-10

Back to the equation:

-(-10z-10)



We get rid of parentheses

12z+10z+10+20=0

We add all the numbers together, and all the variables

22z+30=0

We move all terms containing z to the left, all other terms to the right

22z=-30

z=-30/22

z=-1+4/11

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