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-4(-3x+5)-4x=2(x-3)-5
We move all terms to the left:
-4(-3x+5)-4x-(2(x-3)-5)=0
We add all the numbers together, and all the variables
-4x-4(-3x+5)-(2(x-3)-5)=0
We multiply parentheses
-4x+12x-(2(x-3)-5)-20=0
We calculate terms in parentheses: -(2(x-3)-5), so:We add all the numbers together, and all the variables
2(x-3)-5
We multiply parentheses
2x-6-5
We add all the numbers together, and all the variables
2x-11
Back to the equation:
-(2x-11)
8x-(2x-11)-20=0
We get rid of parentheses
8x-2x+11-20=0
We add all the numbers together, and all the variables
6x-9=0
We move all terms containing x to the left, all other terms to the right
6x=9
x=9/6
x=1+1/2
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