-3z-2/z5

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Solution for -3z-2/z5 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

-3*z-(2/z) < 5 // - 5

-3*z-(2/z)-5 < 0

-3*z-2*z^-1-5 < 0

-3*z-2*z^-1-5 = 0

-1*(3*z+2*z^-1+5) = 0

3*z^1+2*z^-1+5*z^0 = 0

(3*z^2+5*z^1+2*z^0)/(z^1) = 0 // * z^2

z^1*(3*z^2+5*z^1+2*z^0) = 0

z^1

3*z^2+5*z+2 = 0

3*z^2+5*z+2 = 0

DELTA = 5^2-(2*3*4)

DELTA = 1

DELTA > 0

z = (1^(1/2)-5)/(2*3) or z = (-1^(1/2)-5)/(2*3)

z = -2/3 or z = -1

z in { -1, -2/3} 

-1 = 0

-1 = 0

z belongs to the empty set

(z+1)*(z+2/3) < 0

	(-oo:-1)	(-1:-2/3)	(-2/3:+oo)
z+1	-	+	+
z+2/3	-	-	+


z in (-1:-2/3)

(-1:-2/3)

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