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-3z(z+7)(2-2)=0
We add all the numbers together, and all the variables
-3z(z+7)0=0
We multiply parentheses
-3z^2-21z=0
a = -3; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·(-3)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*-3}=\frac{0}{-6} =0 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*-3}=\frac{42}{-6} =-7 $
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