-3y+5(1y-1)=7-6(7-y)

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Solution for -3y+5(1y-1)=7-6(7-y) equation: 



-3y+5(1y-1)=7-6(7-y)

We move all terms to the left:

-3y+5(1y-1)-(7-6(7-y))=0

We add all the numbers together, and all the variables

-3y+5(y-1)-(7-6(-1y+7))=0

We multiply parentheses

-3y+5y-(7-6(-1y+7))-5=0



We calculate terms in parentheses: -(7-6(-1y+7)), so:

7-6(-1y+7)

determiningTheFunctionDomain
-6(-1y+7)+7

We multiply parentheses

6y-42+7

We add all the numbers together, and all the variables

6y-35

Back to the equation:

-(6y-35)



We add all the numbers together, and all the variables

2y-(6y-35)-5=0

We get rid of parentheses

2y-6y+35-5=0

We add all the numbers together, and all the variables

-4y+30=0

We move all terms containing y to the left, all other terms to the right

-4y=-30

y=-30/-4

y=7+1/2

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