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-3x^2-7x+9=0
a = -3; b = -7; c = +9;
Δ = b2-4ac
Δ = -72-4·(-3)·9
Δ = 157
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{157}}{2*-3}=\frac{7-\sqrt{157}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{157}}{2*-3}=\frac{7+\sqrt{157}}{-6} $
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