-3x2-19x-6=0

Solution for -3x2-19x-6=0 equation:

-3x^2-19x-6=0

a = -3; b = -19; c = -6;
Δ = b2-4ac
Δ = -192-4·(-3)·(-6)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-17}{2*-3}=\frac{2}{-6}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+17}{2*-3}=\frac{36}{-6}
=-6
$