-3x2+8=2(x2+4)

Solution for -3x2+8=2(x2+4) equation:

-3x^2+8=2(x2+4)

We move all terms to the left:

-3x^2+8-(2(x2+4))=0

We add all the numbers together, and all the variables

-3x^2-(2(+x^2+4))+8=0


We calculate terms in parentheses: -(2(+x^2+4)), so:

2(+x^2+4)

We multiply parentheses

2x^2+8

Back to the equation:

-(2x^2+8)


We get rid of parentheses

-3x^2-2x^2-8+8=0

We add all the numbers together, and all the variables

-5x^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-10}=0$