-3x/4x2=26

Solution for -3x/4x2=26 equation:

-3x/4x^2=26

We move all terms to the left:

-3x/4x^2-(26)=0


Domain of the equation: 4x^2!=0

x^2!=0/4

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-3x-26*4x^2=0

Wy multiply elements

-104x^2-3x=0

a = -104; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-104)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-104}=\frac{0}{-208}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-104}=\frac{6}{-208}
=-3/104
$