-3x-4x(x-2)=-(x+4)-6

Solution for -3x-4x(x-2)=-(x+4)-6 equation:

-3x-4x(x-2)=-(x+4)-6

We move all terms to the left:

-3x-4x(x-2)-(-(x+4)-6)=0

We multiply parentheses

-4x^2-3x+8x-(-(x+4)-6)=0


We calculate terms in parentheses: -(-(x+4)-6), so:

-(x+4)-6

We get rid of parentheses

-x-4-6

We add all the numbers together, and all the variables

-1x-10

Back to the equation:

-(-1x-10)


We add all the numbers together, and all the variables

-4x^2+5x-(-1x-10)=0

We get rid of parentheses

-4x^2+5x+1x+10=0

We add all the numbers together, and all the variables

-4x^2+6x+10=0

a = -4; b = 6; c = +10;
Δ = b2-4ac
Δ = 62-4·(-4)·10
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-14}{2*-4}=\frac{-20}{-8}
=2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+14}{2*-4}=\frac{8}{-8}
=-1
$