-3x-4x(5x+2)=11x-4

Solution for -3x-4x(5x+2)=11x-4 equation:

-3x-4x(5x+2)=11x-4

We move all terms to the left:

-3x-4x(5x+2)-(11x-4)=0

We multiply parentheses

-20x^2-3x-8x-(11x-4)=0

We get rid of parentheses

-20x^2-3x-8x-11x+4=0

We add all the numbers together, and all the variables

-20x^2-22x+4=0

a = -20; b = -22; c = +4;
Δ = b2-4ac
Δ = -222-4·(-20)·4
Δ = 804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{804}=\sqrt{4*201}=\sqrt{4}*\sqrt{201}=2\sqrt{201}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{201}}{2*-20}=\frac{22-2\sqrt{201}}{-40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{201}}{2*-20}=\frac{22+2\sqrt{201}}{-40}
$