-3x-3(3-4x)=3(x-4)-15

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Solution for -3x-3(3-4x)=3(x-4)-15 equation: 



-3x-3(3-4x)=3(x-4)-15

We move all terms to the left:

-3x-3(3-4x)-(3(x-4)-15)=0

We add all the numbers together, and all the variables

-3x-3(-4x+3)-(3(x-4)-15)=0

We multiply parentheses

-3x+12x-(3(x-4)-15)-9=0



We calculate terms in parentheses: -(3(x-4)-15), so:

3(x-4)-15

We multiply parentheses

3x-12-15

We add all the numbers together, and all the variables

3x-27

Back to the equation:

-(3x-27)



We add all the numbers together, and all the variables

9x-(3x-27)-9=0

We get rid of parentheses

9x-3x+27-9=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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