-3x-2(-2x-8)=16+x

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Solution for -3x-2(-2x-8)=16+x equation: 



-3x-2(-2x-8)=16+x

We move all terms to the left:

-3x-2(-2x-8)-(16+x)=0

We add all the numbers together, and all the variables

-3x-2(-2x-8)-(x+16)=0

We multiply parentheses

-3x+4x-(x+16)+16=0

We get rid of parentheses

-3x+4x-x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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