-3x-(3x-2)=32

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Solution for -3x-(3x-2)=32 equation: 



-3x-(3x-2)=32

We move all terms to the left:

-3x-(3x-2)-(32)=0

We get rid of parentheses

-3x-3x+2-32=0

We add all the numbers together, and all the variables

-6x-30=0

We move all terms containing x to the left, all other terms to the right

-6x=30

x=30/-6

x=-5

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