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-3x+8=x-3x+6-1/2(2x-4)
We move all terms to the left:
-3x+8-(x-3x+6-1/2(2x-4))=0
Domain of the equation: 2(2x-4))!=0We multiply all the terms by the denominator
x∈R
-3x*2(2x-4))-(x-3x+8*2(2x-4))+6-1=0
We add all the numbers together, and all the variables
-3x-3x*2(2x-4))-(x+8*2(2x-4))+6-1=0
Wy multiply elements
-6x^2(2+16x(2-3x=0
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