-3x(x-6)+4(x+1)=7x-10

Solution for -3x(x-6)+4(x+1)=7x-10 equation:

-3x(x-6)+4(x+1)=7x-10

We move all terms to the left:

-3x(x-6)+4(x+1)-(7x-10)=0

We multiply parentheses

-3x^2+18x+4x-(7x-10)+4=0

We get rid of parentheses

-3x^2+18x+4x-7x+10+4=0

We add all the numbers together, and all the variables

-3x^2+15x+14=0

a = -3; b = 15; c = +14;
Δ = b2-4ac
Δ = 152-4·(-3)·14
Δ = 393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{393}}{2*-3}=\frac{-15-\sqrt{393}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{393}}{2*-3}=\frac{-15+\sqrt{393}}{-6}
$