-3x(x-4)=3x+12

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Solution for -3x(x-4)=3x+12 equation: 



-3x(x-4)=3x+12

We move all terms to the left:

-3x(x-4)-(3x+12)=0

We multiply parentheses

-3x^2+12x-(3x+12)=0

We get rid of parentheses

-3x^2+12x-3x-12=0

We add all the numbers together, and all the variables

-3x^2+9x-12=0

a = -3; b = 9; c = -12;
Δ = b2-4ac
Δ = 92-4·(-3)·(-12)
Δ = -63
Delta is less than zero, so there is no solution for the equation

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