-3x(x-1)+7x=2(2x+3)

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Solution for -3x(x-1)+7x=2(2x+3) equation: 



-3x(x-1)+7x=2(2x+3)

We move all terms to the left:

-3x(x-1)+7x-(2(2x+3))=0

We add all the numbers together, and all the variables

7x-3x(x-1)-(2(2x+3))=0

We multiply parentheses

-3x^2+7x+3x-(2(2x+3))=0



We calculate terms in parentheses: -(2(2x+3)), so:

2(2x+3)

We multiply parentheses

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

-3x^2+10x-(4x+6)=0

We get rid of parentheses

-3x^2+10x-4x-6=0

We add all the numbers together, and all the variables

-3x^2+6x-6=0

a = -3; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·(-3)·(-6)
Δ = -36
Delta is less than zero, so there is no solution for the equation

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