-3x(x+6)=-3(2x+4)

Solution for -3x(x+6)=-3(2x+4) equation:

-3x(x+6)=-3(2x+4)

We move all terms to the left:

-3x(x+6)-(-3(2x+4))=0

We multiply parentheses

-3x^2-18x-(-3(2x+4))=0


We calculate terms in parentheses: -(-3(2x+4)), so:

-3(2x+4)

We multiply parentheses

-6x-12

Back to the equation:

-(-6x-12)


We get rid of parentheses

-3x^2-18x+6x+12=0

We add all the numbers together, and all the variables

-3x^2-12x+12=0

a = -3; b = -12; c = +12;
Δ = b2-4ac
Δ = -122-4·(-3)·12
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{2}}{2*-3}=\frac{12-12\sqrt{2}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{2}}{2*-3}=\frac{12+12\sqrt{2}}{-6}
$