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-3x(x+2)+5x=-9
We move all terms to the left:
-3x(x+2)+5x-(-9)=0
We add all the numbers together, and all the variables
5x-3x(x+2)+9=0
We multiply parentheses
-3x^2+5x-6x+9=0
We add all the numbers together, and all the variables
-3x^2-1x+9=0
a = -3; b = -1; c = +9;
Δ = b2-4ac
Δ = -12-4·(-3)·9
Δ = 109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{109}}{2*-3}=\frac{1-\sqrt{109}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{109}}{2*-3}=\frac{1+\sqrt{109}}{-6} $
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