-3x(4x+3)+5(4x+2)=-95

Solution for -3x(4x+3)+5(4x+2)=-95 equation:

-3x(4x+3)+5(4x+2)=-95

We move all terms to the left:

-3x(4x+3)+5(4x+2)-(-95)=0

We add all the numbers together, and all the variables

-3x(4x+3)+5(4x+2)+95=0

We multiply parentheses

-12x^2-9x+20x+10+95=0

We add all the numbers together, and all the variables

-12x^2+11x+105=0

a = -12; b = 11; c = +105;
Δ = b2-4ac
Δ = 112-4·(-12)·105
Δ = 5161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{5161}}{2*-12}=\frac{-11-\sqrt{5161}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{5161}}{2*-12}=\frac{-11+\sqrt{5161}}{-24}
$