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-3x(-x-2)=3(x-2)
We move all terms to the left:
-3x(-x-2)-(3(x-2))=0
We add all the numbers together, and all the variables
-3x(-1x-2)-(3(x-2))=0
We multiply parentheses
3x^2+6x-(3(x-2))=0
We calculate terms in parentheses: -(3(x-2)), so:We get rid of parentheses
3(x-2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
3x^2+6x-3x+6=0
We add all the numbers together, and all the variables
3x^2+3x+6=0
a = 3; b = 3; c = +6;
Δ = b2-4ac
Δ = 32-4·3·6
Δ = -63
Delta is less than zero, so there is no solution for the equation
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