-3v-29=5(1-5v)+5v

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Solution for -3v-29=5(1-5v)+5v equation: 



-3v-29=5(1-5v)+5v

We move all terms to the left:

-3v-29-(5(1-5v)+5v)=0

We add all the numbers together, and all the variables

-3v-(5(-5v+1)+5v)-29=0



We calculate terms in parentheses: -(5(-5v+1)+5v), so:

5(-5v+1)+5v

We add all the numbers together, and all the variables

5v+5(-5v+1)

We multiply parentheses

5v-25v+5

We add all the numbers together, and all the variables

-20v+5

Back to the equation:

-(-20v+5)



We get rid of parentheses

-3v+20v-5-29=0

We add all the numbers together, and all the variables

17v-34=0

We move all terms containing v to the left, all other terms to the right

17v=34

v=34/17

v=2

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