-3v+42=2(v+6)

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Solution for -3v+42=2(v+6) equation: 



-3v+42=2(v+6)

We move all terms to the left:

-3v+42-(2(v+6))=0



We calculate terms in parentheses: -(2(v+6)), so:

2(v+6)

We multiply parentheses

2v+12

Back to the equation:

-(2v+12)



We get rid of parentheses

-3v-2v-12+42=0

We add all the numbers together, and all the variables

-5v+30=0

We move all terms containing v to the left, all other terms to the right

-5v=-30

v=-30/-5

v=+6

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