-3v+33=2(v-1)

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Solution for -3v+33=2(v-1) equation: 



-3v+33=2(v-1)

We move all terms to the left:

-3v+33-(2(v-1))=0



We calculate terms in parentheses: -(2(v-1)), so:

2(v-1)

We multiply parentheses

2v-2

Back to the equation:

-(2v-2)



We get rid of parentheses

-3v-2v+2+33=0

We add all the numbers together, and all the variables

-5v+35=0

We move all terms containing v to the left, all other terms to the right

-5v=-35

v=-35/-5

v=+7

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