-3r+4-(2r-3)=r

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Solution for -3r+4-(2r-3)=r equation: 



-3r+4-(2r-3)=r

We move all terms to the left:

-3r+4-(2r-3)-(r)=0

We add all the numbers together, and all the variables

-4r-(2r-3)+4=0

We get rid of parentheses

-4r-2r+3+4=0

We add all the numbers together, and all the variables

-6r+7=0

We move all terms containing r to the left, all other terms to the right

-6r=-7

r=-7/-6

r=1+1/6

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