-3r+2(2r+3)=2(r+1)

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Solution for -3r+2(2r+3)=2(r+1) equation: 



-3r+2(2r+3)=2(r+1)

We move all terms to the left:

-3r+2(2r+3)-(2(r+1))=0

We multiply parentheses

-3r+4r-(2(r+1))+6=0



We calculate terms in parentheses: -(2(r+1)), so:

2(r+1)

We multiply parentheses

2r+2

Back to the equation:

-(2r+2)



We add all the numbers together, and all the variables

r-(2r+2)+6=0

We get rid of parentheses

r-2r-2+6=0

We add all the numbers together, and all the variables

-1r+4=0

We move all terms containing r to the left, all other terms to the right

-r=-4

r=-4/-1

r=+4

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