-3r+19=3(4-r)=3

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Solution for -3r+19=3(4-r)=3 equation: 



-3r+19=3(4-r)=3

We move all terms to the left:

-3r+19-(3(4-r))=0

We add all the numbers together, and all the variables

-3r-(3(-1r+4))+19=0



We calculate terms in parentheses: -(3(-1r+4)), so:

3(-1r+4)

We multiply parentheses

-3r+12

Back to the equation:

-(-3r+12)



We get rid of parentheses

-3r+3r-12+19=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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