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-3n(3n+6)+8=-82
We move all terms to the left:
-3n(3n+6)+8-(-82)=0
We add all the numbers together, and all the variables
-3n(3n+6)+90=0
We multiply parentheses
-9n^2-18n+90=0
a = -9; b = -18; c = +90;
Δ = b2-4ac
Δ = -182-4·(-9)·90
Δ = 3564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3564}=\sqrt{324*11}=\sqrt{324}*\sqrt{11}=18\sqrt{11}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18\sqrt{11}}{2*-9}=\frac{18-18\sqrt{11}}{-18} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18\sqrt{11}}{2*-9}=\frac{18+18\sqrt{11}}{-18} $
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