-3m+4(1m-4)=-2(1m+6)+2

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Solution for -3m+4(1m-4)=-2(1m+6)+2 equation: 



-3m+4(1m-4)=-2(1m+6)+2

We move all terms to the left:

-3m+4(1m-4)-(-2(1m+6)+2)=0

We add all the numbers together, and all the variables

-3m+4(m-4)-(-2(m+6)+2)=0

We multiply parentheses

-3m+4m-(-2(m+6)+2)-16=0



We calculate terms in parentheses: -(-2(m+6)+2), so:

-2(m+6)+2

We multiply parentheses

-2m-12+2

We add all the numbers together, and all the variables

-2m-10

Back to the equation:

-(-2m-10)



We add all the numbers together, and all the variables

m-(-2m-10)-16=0

We get rid of parentheses

m+2m+10-16=0

We add all the numbers together, and all the variables

3m-6=0

We move all terms containing m to the left, all other terms to the right

3m=6

m=6/3

m=2

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